gradasso

== Italian == === Etymology === Archetypal name from Gradasso, a character in Ludovico Ariosto's Orlando Furioso (1532) === Pronunciation === IPA(key): /ɡraˈdas.so/ Rhymes: -asso Hyphenation: gra‧dàs‧so === Noun === gradasso m (plural gradassi) braggart loudmouth flippant