scaldapiatti

== Italian == === Etymology === Verb-object compound, composed of scalda (“to heat, to warm”) +‎ piatti (“plates”). === Pronunciation === IPA(key): /ˌskal.daˈpjat.ti/ Rhymes: -atti Hyphenation: scal‧da‧piàt‧ti === Noun === scaldapiatti m (invariable) plate warmer === References ===